Springboot入门案例开发步骤_最简SpringBoot程序所包含的基础文件

入门案例开发步骤

①：创建新模块，选择Spring初始化，并配置模块相关基础信息
②：选择当前模块需要使用的技术集
③：开发控制器类

@RestController
@RequestMapping("/books")
public class BookController {
    @GetMapping("/{id}")
    public String getById(@PathVariable Integer id) {
        System.out.println("id ==> " + id);
        return "hello , spring boot! ";
    }
}

④：运行自动生成的Application类

最简SpringBoot程序所包含的基础文件

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 https://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>2.5.0</version>
    </parent>
    <groupId>com.shell</groupId>
    <artifactId>springboot-01-quickstart</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <dependencies>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
        </dependency>
    </dependencies>
</project>

@SpringBootApplication
public class Application {
    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }
}

注意事项：

基于idea开发SpringBoot程序需要确保联网且能够加载到程序框架结构