入门案例开发步骤
①:创建新模块,选择Spring初始化,并配置模块相关基础信息
②:选择当前模块需要使用的技术集
③:开发控制器类
<code class="language-java">@RestController @RequestMapping("/books") public class BookController { @GetMapping("/{id}") public String getById(@PathVariable Integer id) { System.out.println("id ==> " + id); return "hello , spring boot! "; } }</code>
④:运行自动生成的Application类
最简SpringBoot程序所包含的基础文件
<code class="language-xml"><?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 https://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <parent> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-parent</artifactId> <version>2.5.0</version> </parent> <groupId>com.shell</groupId> <artifactId>springboot-01-quickstart</artifactId> <version>0.0.1-SNAPSHOT</version> <dependencies> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-web</artifactId> </dependency> </dependencies> </project> </code>
<code class="language-java">@SpringBootApplication public class Application { public static void main(String[] args) { SpringApplication.run(Application.class, args); } }</code>
注意事项:
基于idea开发SpringBoot程序需要确保联网且能够加载到程序框架结构
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